Question

answer the question​

Answer 1

ℏℓ✺ Պᾰтḙ ❡պ ❤

using the relation, v = 1/2π√LC

we get, v = 1/2π √(10^-5) (10^-9)

= 1590×10^3Hz

= 1590kHz

side band frequencies are = ( 1590+(-)2)

= 1592kHz & 1588kHz

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Answer 2

Check the attachment :)