Question

answer the question
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Answer 1

Answer:

1 ) x = -i/3√mn, y =  i√n/3m

2) x = 2n/3n + 2n², y = n/3 + 2n

Step-by-step explanation:

Question 1:

Given,

x + my = 0

3xy - n = 0

Now,

x + my = 0  => x  = -my  ---- [1]

Substitute [1] in 3xy  - n = 0

3y (-my) - n = 0

-3my² = n

=> y² = -n/3m

=> y = i√n/3m

=> x = - my = -mi√n/3m = -i/3√mn

Question 2:

Given,

nx - 2y = 0 => x = 2y/n ---- [1]

3x + 4y = 2       ---------------- [2]

Now,

Substitute [1] in [2]

3(2y/n) + 4y = 2

y(6/n + 4) = 2

=> y = 2n/6 + 4n = n/3 + 2n

x = 2y/n = 2n/3n + 2n²