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Answer:
15.36 mol/Liter
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Answer:
15.44
Let suppose 100g Solution
in which 69% HNO3 means 69gram
Volume of Solution = M/D
V = 100/1.41= 71ml
[C] = nsolute /V Sol.
[C] = 69/63× 1000/71
[C] = 15.4
Volume in Litre
Mole = Weight /Molecular Weight
Molecular Weight of HNO3 is 63Gram
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