Question

answer the question ​

Answer 1

Step-by-step explanation:

BR,AP , DQ , CQ ARE ANGLE BISECTOR

SO THEY WILL BISECT THR RESPECTIVE ANGLE

IN TRAINGLE DQC

D/2 + DQC + C/2 = 180 eq (1)

( sum of angle of traingle is 180)

IN TRAINGLE ARB

A/2 + ARB+ B/2 = 180 eq(2)

ADDING eq1 and eq 2

A/2 +ARB+B/2 + D/2 + DQC + C/2 = 180 + 180

A/2+ B/2 +C/2+D/2+ ARB+DQC =360

A+B+C+D +ARB+DQC = 360 eq 3

2

{ IN QUADRILATERAL ABCD

A + B + C + D = 360} eq 4

putting eq 4 in eq3

360 +ARB +DQC = 360

2

180 +ARB + DQC = 360

ARB + DQC = 180

similarly

P+ S = 180

HENCE PROVED

MAY IT WILL HELP YOU

SORRY FOR ANY MISTAKE

I DON'T HAVE PAPER NOW SO I CAN SOLVE IT IN THIS WAY

THANK YOU

Answer 2

Step-by-step explanation:

come to my question......