Question

answer the question​

Answer 1

Answer:

$we \: know \: that \\ angle \: sor = 90 \\ in \: triangle \: sor \: \: by \: pythagoras \: theorem \\ {(x + 1)}^{2} = {x}^{2} + {(x - 1)}^{2} \\ {x}^{2} + 2x + 1 = {x}^{2} + {x}^{2} - 2x + 1 \\ after \: solving \: this \: u \: will \: find \: this \: equation \\ {x}^{2} - 4x = 0 \\ x(x - 4) = 0 \\ \bold{ x = 0 \: and \: x = 4}$

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Answer 2

Answer:

Please find the attachment

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