Question

answer the question​

Answer 1

I'm taking theta as x

LHS = sinXcos(90-x) + cosXsin(90-x)

= sinXsinX + cosXcosX

= sin²X + cos²X

= 1

I used the equations

sin(90-x) = cosX and

cos(90-x) = sinX

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Answer 2

Answer:

Hi mate

The answer is given in the attachment.

hope it's help

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