Math, asked by RoshanKumar729, 11 months ago

answer the question​

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Answered by niharikam54
0

Answer:

y ^2 + 6y -216 =0

y^2 +18 y -12y -216 =0

y (y+ 18) -12 (y +18) = 0

(y-12) (y +18) = 0

y = 12 ,-18

Answered by kevinnirmal2k20
0

y2+6y-216=0

By using splitting the middle term

y2+18y-12y-216=0

y(y+18)-12(y+18)=0

(y-12)(y+18)=0

y-12=0

y=12

y+18=0

y=-18

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