Question

answer the question​

Answer 1

Step-by-step explanation:

Your material is in the attachment HOPE IT HELPS

Answer 2

Answer:

see explanation

Step-by-step explanation:

let ∅ be x

GIVEN-

(sinx - 2sin³x) / (2cos³x - cosx) = tan x

LHS-

(sinx - 2sin³x) / (2cos³x - cosx)

⇒sinx(1-2sin²x) / cosx[2(cos²x) -1]

⇒sinx(1-2sin²x) / cosx[2(1-sin²x)-1]        (as cos²x = 1- sin²x)

⇒ sinx(1-2sin²x) / cosx [2 - 2 sin²x -1]    

⇒ sinx(1-2sin²x) / cosx (1-2sin²x)

⇒sinx / cosx                                   (as (1-2sin²x) cancel each other)

⇒tanx

Thus LHS = RHS

Hope this helps.....