Math, asked by suday372366, 9 months ago

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Answered by Anonymous
0

Answer:

3) Let the digits be x and y.

Then, x+y = 9

the original number is 10x+y.

On reversing, we get the new number as 10y+x

The new number is greater than the old number by 27, i.e.

(10y+x) - (10x+y) = 27

or 9y-9x = 27, or y-x = 3

and x+y = 9

Adding the two equations, we get 2y = 12 or y = 6.

Thus, x = 3.

Therefore, the original number is 36.

4) Let the digit in units place = x

The digit in tens place = 3x

The number is 10(3x) + x = 31x

Digits are interchanged

Digit in units place = 3x

Digit in tens place = x

The new number= 10(x) + 3x = 13x

Sum of these two numbers = 88

31x + 13x = 88

44x = 88

x = 2

3x = 6

The original number is 62

5) At present,

Shobo's age = x years

His mother's age = 6 times of Shobo's age = 6x years

Five years from now,

Shobo's age = ( x + 5 ) years

According to the problem given,

x + 5 = one by third of his mother's present age

x + 5 = 6x / 3

x + 5 = 2x

5 = 2x - x

5 = x

Therefore ,

Shobo's present age = x = 5 years

His mother's age = 6x

= 6 × 5

= 30 years

Hope it helps!! Thank you, please mark as brainliest.. :)

Answered by nehalcharola
0

3) let the unit digit=x

= ten's digit=(9-x)

= the original number=10(9-x)+x

=90-10x+x=90-9x

= after interchanging the digits

= We get the new number

= 10x+(9-x)= 10x+9-x=9x+9

= it is given that new number= original number=27

= 9x+9=90-9x+27

= 9x+9x=117-9=108

= 18x=108

= x=6

= the original number=90(9*6)

= 90-54=36

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