Question

Answer the question.

Answer 1

SoluTion:

b) 16 + 5 ÷ 2 - 1

Using one pair of brackets, we've to make the total equal to 21.

→ 16 + 5 ÷ (2 - 1)

→ 16 + 5 ÷ 1

→ 21 ÷ 1

→ 21 ( Answer )

c) 16 + 5 ÷ 2 - 1 + 6

Using two pair of brackets, we've to make the total equal to 21.

→ (16 + 5) ÷ (2 - 1 + 6)

→ 21 ÷ 7

→ 3 ( Answer )

______________________

This sum is solved using BODMAS rule.

B → Brackets

O → Of

D → Division

M → Multiplication

A → Addition

S → Subtraction

Answer 2

✥ Rule to be used :- BODMAS

= Bracket Off Division Multiplication Addition Subtraction.

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(b) Including one pair of brackets to make the total value equal to 21.

→ Statement given : 16 + 5 ÷ 2 - 1

= 16 + 5 ÷ (2 - 1)

= 16 + 5 ÷ 1

= 21 ÷ 1

= 21 → Value

(c) Including two pairs of brackets to make the total value equal to 3.

→ Statement given : 16 + 5 ÷ 2 - 1 + 6

= (16 + 5) ÷ (2 - 1 + 6)

= 21 ÷ 7

= 3 → Value

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