Question

answer the question ​

Answer 1

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Answer 2

Q68

Given ==》

▪︎ 2x³+ax²+3x-5

▪︎ x³+x²-4x+a

To find==》

Value of a

Solution =》

p(x) = 2x³+ax²-3x-5

g(x) = x-2

x-2=0

x=2

putting value of x in p(x)

2x³+ax²+3x-5

2×(2)³+a×(2)²+3×(2)-5

2×8+a×4+6-5

16+4a+6-5

4a+22-5

4a+17

x³+x²-4x+a

putting x=2

2³+2²-4×2+a

8+4-8+a

4+a

4a+17=4+a

4a-a=4-17

3a=-13

a=-13/3

Q69

Given =》

▪︎ x³-3x²+ax-10

To find =》

The value of a so that x-5 is a factor of the polynomial

Solution =》

p(x)= x³-3x²+ax-10

g(x) = x-5

x-5=0

x=5

putting value of x in p(x)

5³-3×5²+a×5-10=0

125-3×25+5a-10=0

125-75+5a-10=0

125-85+5a=0

40+5a=0

5a=-40

a=-8

The value of a is -8

hope IT HELPs u

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