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Heat lost =Heat gained <br> When 1 litre of water from A is mixed with 2 litres of water form B then the equilibrium temperature attained is
16° C
Q = mstraian >= <
tA = 2 x s x *tB - 16
(16- tA) = 2(tB- 16)
2tB+tA = 18 - (1)
<br> When 2 litres of water from A is mixed with 2 liters of water from B then the equilibrium temperture of the mixture is
41°C
2xsx(14- tA) = 2xsx(tB- 14)
14-tA = tB - 14
tB + tA = 28 - 2
2tB + 2tA = 56 - 3
3 - (1) -> tA = 8° C
tB + tA = 28
tB = 28 - tA = 28 - 8- 20 ° C
I hope my answer will help you.
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