Question

Answer the question ​

Answer 1

Answer:

ok

Explanation:

please mark as brainleast

Answer 2

Question :

★ Two resistors 3ohm and 6ohm are first connected in series and then in parallel. Find the ratio of effective resistances...

Answer :

Formulae used -

• Net resistance in series = R1 + R2 + R3+...

• Net resistance in parallel = $\frac{1}{R1} +\frac{1}{R2}+\frac{1}{R3} +....$

Solution -

Resistance in series = (6+3)ohm = 9ohm

for, Resistance in parallel =

$\frac{1}{R1} = \frac{1}{6} + \frac{1}{3} = \frac{1 + 2}{6} = \frac{1}{2}$

R(in parallel) = 2

so,

ratio would be

${\huge{\boxed{\bf{9:2}}}}$