Question

answer the question​

Answer 1

Solution :-

Given ,

• x + ( 1/x ) = 3

We need to find ,

• x² + ( 1/x² ) = ?

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x + ( 1/x ) = 3

By S.O.B.S ( Squaring on both sides )

⇒ [ x + ( 1/x ) ]² = 3²

Simplifying using ,

• ( a + b )² = a² + 2ab + b²

⇒ x² + 2 ( x ) ( 1/x ) + ( 1/x )² = 9

⇒ x² + 2 ( 1 ) + 1²/x² = 9

⇒ x² + 2 + 1/x² = 9

⇒ x² + 1/x² = 9 - 2

[ °.° 2 is transposed to RHS it subtracts itself from RHS . So , 2 is negative ( - ve )

⇒ x² + 1/x² = 7

Hence , x² + 1/x² = 7

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More information :-

Algebraic identities

• ( a + b )² = a² + 2ab + b²
• ( a - b )² = a² - 2ab + b²
• ( a + b ) ( a - b ) = a² - b²
• a² + b² = ( a + b )² - 2ab
• ( a + b + c )² = a² + b² + c² + 2 [ ab + bc + ac ]

Answer 2

Answer:

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