Question

Answer the Question ​

Answer 1

Question:

$\frac{ {3}^{2x + 1} }{9} = 81$

Answer:

Now express the value of 81 in form of 3 to the power

$\frac{ {3}^{2x + 1} }{9} = {3}^{4}$

Now get 9 in the side opposite to x in form of 3 to the power

${3}^{2x + 1} = {3}^{4} \times {3}^{2}$

${3}^{2x + 1} = {3}^{6}$

Now both the terms have common base so can equalize the powers of terms

$2x + 1 = 6$

$2x = 5$

$x = \frac{5}{2}$

Be delighted :)

Answer 2

Question:

\frac{ {3}^{2x + 1} }{9} = 81932x+1=81

Answer:

Now express the value of 81 in form of 3 to the power

\frac{ {3}^{2x + 1} }{9} = {3}^{4}932x+1=34

Now get 9 in the side opposite to x in form of 3 to the power

{3}^{2x + 1} = {3}^{4} \times {3}^{2}32x+1=34×32

{3}^{2x + 1} = {3}^{6}32x+1=36

Now both the terms have common base so can equalize the powers of terms

2x + 1 = 62x+1=6

2x = 52x=5

x = \frac{5}{2}x=25

Be delighted :)