Question

Answer the question ​

Answer 1

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$\huge \bigstar \: \red {\underline{{\mathcal{A} \mathfrak{nswer}} }} \: \bigstar \:$

• $\sf{Here, f(x)={6x}^{2} −3−7x}$
• $\sf{ \implies6 {x}^{2} - 7x - 3}$
• $\sf{ \implies6{x}^{2}−9x+2x−3}$
• $\sf{ \implies3x(2x−3)+1(2x−3)}$
• $\sf{ \implies(2x−3)(3x+1)}$

Then,

• f(x) = 0

So,

• 2 x− 3 = 0 and 3x + 1 = 0.

$\longmapsto \: \sf{ \: 3x=3 and 3x−1.}$

★ then ,

$\star \: \: \huge \sf{x = \frac{3}{2} ,x = \frac{ - 1}{3} }$

THE ANSWER IS :

$\small \sf{ \therefore \: The \: zeros \: of \: the \: polynomials \: are} \ \: : \\ \\ \implies \huge \sf{ \frac{3}{2} \: , \: \frac{ - 1}{3} }$

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