Question

answer the question!!!!!! ​

Answer 1

Given:-

• Mass of object = 3.0kg

• Acceleration = 9m/s²

To Find:-

• Force applied on the object.

Formulae used:-

• F = ma

Where,

• m = Mass
• a = Acceleration
• F = force

Therefore,

• → F = ma

• → F = 3 × 9

• → F = 27N

Hence, The Force applied to object is 27N.

EXTRA INFORMATION:-

• Acceleration is vector quantity as it has both magnitude and Direction

• Mass is defined as the quantity in the object.

• Rate of the change in momentum is equal to the force applied to the body.

Answer 2

Given:-

• Mass = 3kg
• acceleration = 0m/s²

To find:-

• force applied

Formula to be used:-

• $\underline{\boxed{\bf force = mass×accelaration}}$

Solution:-

$\longrightarrow$ force = 3 × 0

$\longrightarrow$ Force = 0 N

Additional information:-

Other formula of force:-

when there is a change in momentum, a force is applied to our body !

$\longrightarrow$ $\underline{\boxed{\bf force = \dfrac{mv-mu}{t}}}$

here:-

• mv = final momentum (mass × final velocity)
• mu = initial momentum (mass × initial velocity)
• t = time taken