Math, asked by jpatar16, 1 year ago

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Answered by vksundariob
1

Sin 2A = 2tanA / (1 + tan square A)

Cos 2A =

(1- tan square A) /(1+ tan square A)

Tan 2A = 2 tanA /(1 - tan square A)

(Or) tan 2A, = sin2A/cos2A

Use the above formulae with the given value of tan theeta and find out the values of sin2A, cos2A, tan 2A

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