Math, asked by rohans24, 1 year ago

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Answered by ishitamogha21
1
1/secø-tanø=secø+tanø
LHS
1/secø-tanø
on rationalising the denominator
1/secø-tanø×secø+tanø/secø+tanø
secø+tanø/sec²ø-tan²ø
secø+tanø/1 (identity=sec²ø-tan²ø=1)
secø+tanø=RHS

HENCE,PROVED

hope this answer will help
Answered by aakashvishwakarma58
0
hope its help for you
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