Question

answer the question

Answer 1

75 degree is the correct answer

Answer 2

$\huge\textbf{Solution}$

Let /_CAP = β and /_CBP = α

Now...

CA = CP

In a ∆PAC

/_CAP = /_APC = β

similarly CB = CP and ∠CPB = ∠PBC = α

Now

In the ∆APB,

/_PAB + /_PBA + /_APB = 180°  

As sum of the interior angles in a triangle is 180°

β + α + (β + α) = 180°

2α + 2β = 180°

α + β = 90°

So...

/_APB = α + β = 90°

/_ APB = 90°