Question

answer the question​

Answer 1

Answer:

【H】【e】【y】

Step-by-step explanation:

Hᴇʀᴇ ɪɴ ᴛʜᴇ Aᴛᴛᴀᴄʜᴍᴇɴᴛ

Answer 2

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______________
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step-by-step explanation:



Given: Two poles of heights 'a' and 'b' are apart at a distance of 'p'.

Lines of their heights and opposite feet are joined intersecting at pt E.

A line is drawn to the BC from E intersecting at F,

where EF = h

and,

FC = m

To prove : h = $\frac{ab}{(a+b)}$

Proof :

In ∆ ABC and ∆EFC,

angle ACB = angle ECF ( common )

angle ABC = angle EFC = 90°

angle BAC = FEC ( corresponding angles as AB || EF )

so,

by AAA similarity criteria,

∆ ABC ~ ∆ EFC

=> a/h = p/m

=> m = ph/a ........................(i)

now,

similarly,

we can prove,

∆ BCD ~ ∆ BFE

=> b/h = p/(p-m)

=> p- m = ph/b

=> m = p - ph/b

now,

putting the value of m from eqn (i),

we get,

=> ph/a = p - ph/b

=> ph(1/a + 1/b ) = p

=> h ( 1/a + 1/b ) = 1

=> h { (a+b)/ab } = 1

=> h = ab/(a+b)

therefore,

h = $\frac{ab}{(a+b)}$

Hence,

Proved..