Math, asked by Blaze222, 1 year ago

Answer the question.....​

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Blaze222: Anyonee pls answer

Answers

Answered by Anonymous
10

\underline{\underline{\bold{Question:}}}\\\\\\

\bold{Simplify:}\\\\\\\tt{cos\theta\sqrt{1+tan^2\theta}+sin\theta\sqrt{1+cot^2\theta.}}\\\\\\

\mathfrak{Answer:}

= 2 .

\mathfrak{Step-by-Step\:Explanation:}

\tt{=cos\theta\sqrt{1+tan^2\theta}+sin\theta\sqrt{1+cot^2\theta}}\\\\\\\boxed{\bold{1+tan^2\theta=sec^2\theta\quad\&\quad 1+cot^2\theta=cosec^2\theta}}\\\\\\\tt{=cos\theta\sqrt{sec^2\theta}\:+\:sin\theta\sqrt{cosec^2\theta}}\\\\\\\tt{=cos\theta\:sec\theta\:+\:sin\theta\:cosec\theta}\\\\\\\boxed{\bold{sec\theta=\dfrac{1}{cos\theta}\quad\&\quad\:cosec\theta=\dfrac{1}{sin\theta}}}\\\\\\\tt{=cos\theta\times\dfrac{1}{cos\theta}+sin\theta\times\dfrac{1}{sin\theta}}\\\\\\\tt{=1+1=2.}


Blaze222: Thanks
Anonymous: :)
Anonymous: Ur Welcome.
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