Question

answer the question​

Answer 1

$\large{letthezeroesbeX}$

$\large{givenzeroes=3+√2,3-√2}$

$x = 3 + \sqrt{2}$

$x - 3 - \sqrt{2 } = 0......(1)$

$x = 3 - \sqrt{2}$

$x - 3 + \sqrt{2} .......(2)$

$\large{multipying(1)and(2)}$

$(x - 3 - \sqrt{2} )(x - 3 + \sqrt{2} ) = 0$

$\large{(a+b)(a-b)=asq-bsq}$

$(x - 3) {}^{2} - ( \sqrt{2} {}^{2} ) { = 0}^{}$

${x }^{2} + 9 - 6x - 2 = 0$

${x}^{2} - 6x + 7 = 0$

$\large{reqiuredquadraticequation}$