Physics, asked by yadavlanshi, 4 months ago

answer the question above.pls .
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Answered by Athul4152
1

b) total distance = (3×2)+(5×2)+(1/2(8×5))+(16/2×2)

= 6 + 10 + 20 + 16

= 52m

at 2s

= 2×2 = 4 m

between 2s and 12 second

= 52 m

after 12 second

= 1/2 ( 6×3)

= 9m

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