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Answer:
Step-by-step explanation:
abx²+(b²-ac)x-bc=0
abx²+b²x-acx-bc=0
bx(xa+b)-c(ax+b)=0
(ax+b)(bx-c)=0
ax+b=0
ax=-b
x=-b/a
bx-c=0
bx=c
x=c/b
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