Question

answer the question and give me image how it is solve

Answer 1

let first zero =A=7+√3,

second zero=B=7-√3,

then

Sum of zeores=(7+√3)+(7-√3),

=14

product of zeros=(7+√3)(7-√3),

=(7²-√3²),

=49-3=46,

therefore

quadratic equation will be

x²-(sum of zeroes)x+product of zeroes=0,

x²-14x+46=0

Answer 2

Answer :-

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Given ,

The zeros of the quadratic polynomial are ( 7 + √3 ) , ( 7 - √3 )

Now , let the polynomial be ax² + bx + c

• We know that ,

( i ) Sum of the zeros = - b / a

=> 7 + √3 + 7 - √3 = - b / 1 [ • Scene here , a = 1 ]

=> 14 = - b

=> b = - 14

And ,

( ii ) Product of the zeros = c / a

=> ( 7 + √3 ) ( 7 - √3 ) = c / 1 [ • Scene here , a = 1 ]

=> ( 7 )² - ( √3 )² = c

=> 49 - 3 = c

=> c = 46

• Therefore , the quadratic polynomial is

= ax² + bx + c

= x² + ( - 14 )x + 46

= x² - 14x + 46 [ ★ Required answer ]

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