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Given x = -2 and y = 6.
Given Equation is 3ax + 2ay = 6 --------- (1)
Substitute x = -2 and y = 6 in (1), we get
= > 3a(-2) + 2a(6) = 6
= > -6a + 12a = 6
= > 6a = 6
= > a = 1.
Therefore the value of a = 1.
Now,
= > 2(a - 1) + 2(3b - 4)
= > 2(1 - 1) + 2(3b - 4)
= > 2(3b - 4)
= > 6b - 8
Your question is incorrect!
Given Equation is 3ax + 2ay = 6 --------- (1)
Substitute x = -2 and y = 6 in (1), we get
= > 3a(-2) + 2a(6) = 6
= > -6a + 12a = 6
= > 6a = 6
= > a = 1.
Therefore the value of a = 1.
Now,
= > 2(a - 1) + 2(3b - 4)
= > 2(1 - 1) + 2(3b - 4)
= > 2(3b - 4)
= > 6b - 8
Your question is incorrect!
Mohit123Sharma:
at last it will be 6b-8
not 6b-4
ok
Answered by
0
With the given information x=-2,y=6 we can find the value of a in the equation:
3ax+2ay=6
3a(-2)+2a(6)=6
-6a+12a=6
6a=6
a=6/6
a=1
now we know that a =1
2(a-1)+2(3b-4)
2(1-1)+2(3b-4)
6b-8.
This can't be further evaluated as there is no RHS for the equation 2(a-1)+2(3b-4).
3ax+2ay=6
3a(-2)+2a(6)=6
-6a+12a=6
6a=6
a=6/6
a=1
now we know that a =1
2(a-1)+2(3b-4)
2(1-1)+2(3b-4)
6b-8.
This can't be further evaluated as there is no RHS for the equation 2(a-1)+2(3b-4).
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