Math, asked by karunabscbl, 1 year ago

answer the question attached ​

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Answered by ares10
1

25y²+10y+1=0

25y²+(5y+5y)+1=0

5y(5y+1)+1(5y+1)=0

(5y+1)(5y+1)=0

5y+1=0

y=1/5

Answered by MrBhukkad
1

Step-by-step explanation:

Hey, mate

1 + 25y² + 10y = 0

or, 25y² + 10y + 1 = 0

or, 25y² + (5+5)y + 1 = 0

or, 25y² + 5y + 5y + 1 = 0

or, 5y(5y+1) + 1(5y+1) = 0

or, (5y + 1)(5y + 1) = 0

So, 5y + 1 = 0

or, 5y = -1

or, y = -1/5

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