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We know that the angles on a straight line are called a linear pair and their measures will add up to 180°.
Sum of all the angles =180°
Measure of the first angle=40°
Measure of the second angle =4x
Measure of the third angle=3x
We can write this as an equation as:-
Thus, the value of x=20
Which means :-
The measure of the first angle:-
The measure of the second angle:-
Thus, the measure of the second angle =80°
The measure of the third angle:-
Thus, the measure of the third angle =60°
As the measure of all these angles is adding up to form 180°, we can conclude that we have found out the correct value of x.
Therefore, the value of x =20°
Given :-
QP || RS
Which will mean :-
RQ is the transversal on the lines QP and RS.
Let the angle near angle ∠PQR be x .
= ∠QRS + ∠x = 180°(interior angles on the same side of transversal)
Thus, ∠x =50°
We can see that :-
∠x, ∠PQR and ∠XPQ are forming a triangle.
Which means:-
∠XPQ = 180 - ∠OPQ (linear pair)
So, the three angles of the triangle are=70°,50° and ∠PQR.
Then :-
Thus, the measure of ∠PQR=60°
Therefore, the measure of ∠PQR will be=60°