answer the question below, please
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5
The average height of students of the class is 165.2
Step-by-step explanation:
The highest frequency is 15.
•°• The modal class will be 162-168.
•°• l = 162
f0 = 7
f1 = 15
f2 = 8
h = 6
Mode =
=l + ( \frac{f1 - f0}{2f1 - f0 - f2} ) \times hl+(
2f1−f0−f2
f1−f0
)×h
=162 + (\frac{15 - 7}{2 \times 15 - 8 - 7} ) \times 6162+(
2×15−8−7
15−7
)×6
=162 +(\frac{8}{15} ) \times 6162+(
15
8
)×6
=162 + ( \frac{8}{5} ) \times 2162+(
5
8
)×2
=162 + 1.6 \times 2162+1.6×2
=162 + 3.2162+3.2
=165.2165.2
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Answered by
1
Answer:
Your answer will be 165.2165.2
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