answer the question by observing photo
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hey friends !!
given
cos¢+sin¢=√2cos¢
(cos¢+sin¢)²= (√2cos¢)² {squaring on both side}
= > cos²¢+sin²¢+2sin¢×cos¢=2cos²¢
=>sin²¢= - cos²¢ - 2 sin¢×cos¢ +2 cos²¢
=> sin²¢+sin²¢= cos²¢ -2cos¢×sin¢ +sin²¢
{adding sin²¢ on both side we get )
=>2sin²¢=( cos¢ - sin¢ ) ²
=>(cos¢- sin¢)²= √2cos²¢
=>cos¢- sin¢=√2 cos¢ prooved here .
hope it helps you .!!
@Rajukumar111
given
cos¢+sin¢=√2cos¢
(cos¢+sin¢)²= (√2cos¢)² {squaring on both side}
= > cos²¢+sin²¢+2sin¢×cos¢=2cos²¢
=>sin²¢= - cos²¢ - 2 sin¢×cos¢ +2 cos²¢
=> sin²¢+sin²¢= cos²¢ -2cos¢×sin¢ +sin²¢
{adding sin²¢ on both side we get )
=>2sin²¢=( cos¢ - sin¢ ) ²
=>(cos¢- sin¢)²= √2cos²¢
=>cos¢- sin¢=√2 cos¢ prooved here .
hope it helps you .!!
@Rajukumar111
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