Question

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A pebble is thrown vertically upwards with a speed of 20ms^-1. How high will it be after 2 seconds ( take g=10ms^-2)

Answer 1

20 m

Explanation:

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Answer 2

Answer:

height after 2 s of throw = 20 m

Explanation:

sign convention :

up : +ve

down : -ve

u = 20 m/s

a = -10 m/sq-sec

t = 2 s

s = ut + 1/2 a t^2

= 20×2 + (1/2) (-10) 2×2

= 40 - 20

= 20 m

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