Question

answer the question correct plzzzzzzzzz

Answer 1

$\huge \boxed {\textt {\fcolorbox{Answer ={ [{(v^2/r)}^2 +{a}^{2}]^{1/2} } }}}$

The instantaneous acceleration Ar pointing towards the center of the circle is called Radial acceleration. The radial component causes a change in direction and its magnitude is given by $\huge {Ar}={v}^{2} /{r}$

where r is the radius of curvature at the point in question.

The tangential component causes a change in speed and its magnitude is given by At = dv/dt = a m/sec2 (given)

The tangential acceleration of the car has a constant magnitude of At = A m/sec2

The components Ar and At are perpendicular to each other and the magnitude of a is given by

resultant acceleration.

$\huge {A}^2={At}^{2}+ {Ar}^{2}\\\\ Resultant Acceleration =[ {A}^{2}+({v}^{2} /r)^{2}] ^ {1/2} \\\\ =[ {A}^{2}+({v}^{4}/{r}^{2}) ]^{1/2}$