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Step-by-step explanation:
(perpendicular)AB = 24
perpendicular)AB = 24(base)BC = 7
by using Pythagoras theorem we can find hypotenuse(AC)
AC^2 = AB^2 + BC^2
AC^2 = (24)^2 + (7)^2
AC^2 = 576 + 49
AC^2 = 625
AC = √625
AC = 25
∆ABC RIGHT ANGLED AT B
sinA = perpendicular/hypotenuse
sinA = BC/AC
sinA = 7/25
cosA = base/hypotenuse
cosA = AB/AC
cosA = 24/25
sinC = perpendicular/hypotenuse
sinC = AB/AC
sinC = 24/25
cosC = base/hypotenuse
cosC = 7/25
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