Question

Answer the question fasssssst

Answer 1

this is ur ans

I know the handwriting is bad but the and is full proof

Answer 2

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Given: Two circles with the same centre O and AB is a chord of the larger circle that touches the smaller circle at P.

To prove: AP = BP.

Construction: Join OP.

Proof: AB is a tangent to the smaller circle at the point P and OP is the radius through P.

Therefore,

OP is perpendicular to AB.

But, the perpendicular drawn from the center of a circle to a chord bisects the chord.

Therefore, OP bisects AB.

Hence, AP = BP.