Math, asked by aayushi7532, 1 year ago

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Answered by viswabhargav
1

Let the given lines be l1, l2 and l3.

Intersection of l1 and l2 is A=(-2,0)

Intersection of l2 and l3 is B=(-42,-16)

Intersection of l3 and l1 is C=(-6/11,-24/11)

So ABC is a triangle.

Now midpoints of AB, BC and CA be D, E and F.

D=(-22,-8),E=(-234/11,-100/11) and F=(-14/11,-12/11)

Now AE, BF and CD form medians.

So using two point formula we get

AE as 25x−53y+50=0

BF as 47x+112y+182=0

CD as 16x−59y−120=0

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