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Find Value of k for which equations kx + 27-1=0 and
+6x + 4y - 250, will have infinitely many solution.
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there must be term 'y' for the coefficient 27..
if it's present..the solution is, as below:
generally for infinitely many solutions,
x1 coeff./x2 coeff =y1 coeff./y2 coeff.
k/6=27/4
k=81/2
k=40.5
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