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Hey !!
Here is your answer...
The 1st term which Is divisible by 8 between 200 and 500 is 208.
last term divisible by 8 is 496.
so,
first term ( a ) = 208
common difference ( d ) = 8
Tn = a + (n-1) d
496 = 208 + (n-1) ( 8 )
496 - 208 = (n-1) 8
288/8 = n - 1
n - 1 = 36
n = 36 + 1
n = 37
Hence, there are 37 integers between 200 and 500 which is divisible by 8.
Hope it helps you..
Thanks
^-^
Here is your answer...
The 1st term which Is divisible by 8 between 200 and 500 is 208.
last term divisible by 8 is 496.
so,
first term ( a ) = 208
common difference ( d ) = 8
Tn = a + (n-1) d
496 = 208 + (n-1) ( 8 )
496 - 208 = (n-1) 8
288/8 = n - 1
n - 1 = 36
n = 36 + 1
n = 37
Hence, there are 37 integers between 200 and 500 which is divisible by 8.
Hope it helps you..
Thanks
^-^
Anny121:
thanks a lot friend
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