^Answer the question from the attachment^ ( Solve the numerical )
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the resistance of an ideal ammeter is zero.
bulb A- P=90W V=120V I=?
P=VI
I=P/V
I=90/120
I=0.75A
bulb B- P=60W V=120V. I=?
P=VI
I=P/V
I=60/120
I=0.5A
bulb A- P=90W V=120V I=?
P=VI
I=P/V
I=90/120
I=0.75A
bulb B- P=60W V=120V. I=?
P=VI
I=P/V
I=60/120
I=0.5A
Anny121:
thanks Jiya
wlcm
plz mark it as the brainliest if u like it
very well written
thanx
obviously there shiuld be 2 answers to mark as brainliest
u have answered alone
so it is not possible to mark as BRAINLIEST
then let me give a bakwas answer
hua...ab mark kr do usko....
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