Question

answer the question from the pic question 10​

Answer 1

We know, that both the Δ r right angle Δ

therefore, to prove that
ΔABC≈ΔFED

<B =<E (Right angel Δ)

<A =<F(given)

BC =ED(given)

Therefore, ΔABC≈ΔFED.


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Answer 2

this is congruent by RHS because angle b and angle e both are right angle and BC equal to DE and the hypotenuse of RHS is equal

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