Answer the question given Above
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Step-by-step explanation:
given,
internal diameter=24cm
internal radius=24/2=12cm
external diameter=25 cm
external radius =25/2=12.5cm
The surface area of internal bowl=2πr²
=2(22/7)(12²)
=2×22×12×12/7
=905.14cm²
The surface area of external bowl=2πR²
=2(22/7)(12.5²)
=2×22×12.5×12.5/7
=982.14cm²
The surface area of ring=π(R²-r²)
=22/7(12.5²-12²)
=22/7(12.25)
=22×12.25/7
=38.5cm²
cost of internal bowl=905.14×0.05=Rs.45.25
cost of external bowl=982.14×0.05=Rs.49.1
cost of ring=38.5×0.05=Rs.1.925
cost of bowl=45.25+49.1+1.9=96.25 rupees approx
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