Question

Answer the question given in the attachment.

Answer 1

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Answer 2

Heya Mate :p

C'mon do it a simpler way ^^"

We have :

$\vec{be} + \vec{dc} = \vec{bg} + \vec{ge} + \vec{dg} + \vec{gc}$

( where G is the intersection of the Line Segments BE and DC )

$= ( \vec{bg} + \vec{gc}) + ( \vec{dg} + \vec{ge})$

And following the Vector Law of Addition :p [ For reference =_= Please Draw A Figure ]

$= \vec{bc} + \vec{de}$

But by Mid-point Theorem

( Mid - point theorem says : When you pick Mid-points of any two sides of a Triangle, and join them, Tadaa ! What you get is a Line Segment which measures Half of the Third Side in Length )

$= \vec{bc} + \frac{1}{2} \vec{bc} = \frac{3}{2} \vec{bc}$

And so, probably Your Answer is : ( 2 )