Answer the question given in the attachment.
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Since h2 is greater than h1 , so ,
P.E = mgh will be greater of the stone which is located at h2 height...
K.E = P.E (law of conservation of energy)
The stone located at h2 has more K.E hence exerts more force...
P1 of stone 1 = m(v1) ....Note V1 < V2 ( since stone 2 is falling from h2)
P2 of stone 2 = m(v2) ....
P1 < P2...
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