Question

Answer the question given in the attachment above...!!
Describe the following sets in Set-Builder form.​

Answer 1

Answer: actually you can do this in many ways.i will give you some, you can find many more.

1. { x: x is a whole number and x<1}

  { x: x=0}

2. {x: x is an integer and -1≤x≤3}

4.{x:x is a +ve even integer≤6 and x is a -ve odd integer≥ -5 and x can be=0}

3. this one a bit tricky...

 ok lets see.. i hope im correct

here the numerators follow a clear pattern 1,2,3,4,5,6,and 7

but as for the denominators,

first one's denominator is two

now notice that the second fractions's denominator is actually the sum of the numerator of itself and denominator of 1st fraction + 1

now the 3rd fraction's denominator is the sum of the numerator of itself and denominator of 2nd fraction +2

the 4th fraction denominator is the sum of the numerator of itself and denominator of 3rd fraction +3

and it goes on...      

(i dont know if you're understanding this. plzz bear in mind that typing is harder than explaining)

so it follows a pattern

$\frac{1}{2} ,\frac{2}{2+2+1} ,\frac{3}{5+3+2} ...$

so...lets write set builder

{x:x=p/q where p∈N,p≤7 and q=2 when p=1, q=5 when p=2, q=10 when p=3,

q=17 when p=4, q=26 when p=5,q=37 when p=6 and q=50 when p=7}

  now one thing to note is that

{x:x=p/q where p∈N,p≤7 and q=2,5,10,17,26,37,50} →→THIS is wrong

because the roster form turns out as 1/2,1/5,1/10,1/17,1/26....

so that wont work as q can take any value given,for the numerator...u get it

however

{x:x=p/q where p∈N,p≤7 and q=2 when p=1, q=5 when p=2, q=10 when p=3,

q=17 when p=4, q=26 when p=5,q=37 when p=6 and q=50 when p=7}

↑↑↑this one will work

if u find a way to use the pattern i mentioned before into the set builder form instead of using this above method plzz do tell me:)

hope it helps...........

Answer 2

Answer:

actually you can do this in many ways.i will give you some, you can find many more.

1. { x: x is a whole number and x<1}

{ x: x=0}

2. {x: x is an integer and -1≤x≤3}

4.{x:x is a +ve even integer≤6 and x is a -ve odd integer≥ -5 and x can be=0}

3. this one a bit tricky...

ok lets see.. i hope im correct

here the numerators follow a clear pattern 1,2,3,4,5,6,and 7

but as for the denominators,

first one's denominator is two

now notice that the second fractions's denominator is actually the sum of the numerator of itself and denominator of 1st fraction + 1

now the 3rd fraction's denominator is the sum of the numerator of itself and denominator of 2nd fraction +2

the 4th fraction denominator is the sum of the numerator of itself and denominator of 3rd fraction +3

and it goes on...

(i dont know if you're understanding this. plzz bear in mind that typing is harder than explaining)

so it follows a pattern

\frac{1}{2} ,\frac{2}{2+2+1} ,\frac{3}{5+3+2} ...

2

1

,

2+2+1

2

,

5+3+2

3

...

so...lets write set builder

{x:x=p/q where p∈N,p≤7 and q=2 when p=1, q=5 when p=2, q=10 when p=3,

q=17 when p=4, q=26 when p=5,q=37 when p=6 and q=50 when p=7}

now one thing to note is that

{x:x=p/q where p∈N,p≤7 and q=2,5,10,17,26,37,50} →→THIS is wrong

because the roster form turns out as 1/2,1/5,1/10,1/17,1/26....

so that wont work as q can take any value given,for the numerator...u get it

however

{x:x=p/q where p∈N,p≤7 and q=2 when p=1, q=5 when p=2, q=10 when p=3,

q=17 when p=4, q=26 when p=5,q=37 when p=6 and q=50 when p=7}

↑↑↑this one will work

if u find a way to use the pattern i mentioned before into the set builder form instead of using this above method plzz do tell me:)

hope it helps...........