Question

Answer the question given in the attachment

☆ If you don't know kindly don't answer ​

Answer 1

Answer:

Option-c

Explanation:

For first case of dropping from balloon, initial velocity of stone is zero.

h=21​gt2 -----------(1)

If thrown upward with speed u, then-

−h=ut1​−21​gt12​ taking upward direction as positive --------(2)

And for throwing down-

−h=−ut2​−21​gt22​ ---------------(3)

Now (2)−(3)--

0=u(t1​+t2​)−2g​(t12​−t22​)

⟹u(t1​+t2​)=2g​(t1​+t2​)(t1​−t2​)

⟹u=2g​(t1​−t2​)

From (3)-

h=ut2​+21​gt22​=21​gt1​t2​

⟹21​gt2=21​gt1​t2​

⟹t=t1​t2​

​

Answer 2

Answer:

opition B,

I am also fine,

gald to meet again,

have a beautiful and blessed day ahead friend❣❣