Question

Answer The Question in attachment.

Answer 1

name of alcohol is ethanol and name of acid form by oxidation by kmno4 is ethanoic acid

Answer 2

Answer:

Before Answering, Let's revise some Important Notes:

When Acetic acid reacts with ethanol in the presence of Concentrate H2SO4 as to produce ethyl ethanoate.

Reaction:

$\mathsf{CH {\tiny3}COOH} + \mathsf{ C {\tiny2}H {\tiny5}0H} \: \: \: \underline{ \rightarrow{concentrate \: H2SO4}} \: \: \: \: \mathsf{CH {\tiny3}COOC{ \tiny2}H{ \tiny5}} + H{ \tiny2}O$


Some More Notes About Ethyl ethanoate!

➡ Since ester is formed in this process , the reaction is also known as Esterification.

➡ It ester reacts with H20 in the presence of acids , Acetic acid and ethanol is produced.

➡ Ester are sweet smelling Compounds, therefore there are used in ice creams , drinks and sweets.

Now, Considering on Question Statement!

From Above reaction, we can see When ester reacts with ETHANOL then Ethyl ethanoate is produced.

Therefore, Required Compound X is (Ethyl ethanoate)


General Formula of Ethyl ethanoate :


$\implies{\mathsf{CH {\tiny3}COOC{ \tiny2}H{ \tiny5}}}$


In this Question, it is Given that ,"Treating with Alkanes KMNO4 , gives the same Carboxylic acid (Acetic acid).

Now, See this Statement by Reaction!

C2H5OH + 2(0) (KMNO4) --------> CH3COOH + H2O
-------------

Thus, Required Acid (Carboxylic acid) as Ethanol.

Required Compound (Ethyl ethanoate) as CH3COOC2H5.


Thanks!