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correct answer is AG=4.50
hope it helps you
hope it helps you
vaibhavbhandari:
how it is 4.50
Answered by
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given,
AB II CD II EF II GH
HF=FD=DB
AC = 1.5 CM
proof,
if AB II CD
THEN DB II AC (SINCE HF AND DB ARE EQUAL)
IF DB II AC THEN,
FD II EC
FH II EG
IF AC =1 .5 CM
BD II AC AND BD = AC
III'LY,
IF BD II AC AND BD=AC
THEN
FD = EC
FH = EG
BD = FD = HF (GIVEN)
THEREFORE AB = CE = EG
AB + CE + EG = AG
1.5+1.5+1.5=AG
4.5cm =AG
HENCE PROVED
AB II CD II EF II GH
HF=FD=DB
AC = 1.5 CM
proof,
if AB II CD
THEN DB II AC (SINCE HF AND DB ARE EQUAL)
IF DB II AC THEN,
FD II EC
FH II EG
IF AC =1 .5 CM
BD II AC AND BD = AC
III'LY,
IF BD II AC AND BD=AC
THEN
FD = EC
FH = EG
BD = FD = HF (GIVEN)
THEREFORE AB = CE = EG
AB + CE + EG = AG
1.5+1.5+1.5=AG
4.5cm =AG
HENCE PROVED
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