Question

answer the question in the above attachment

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Answer 1

Step-by-step explanation:

(i)BUC={3,4,5,6,7,8}

AU(BUC)={1,2,3,4,5,6,7,8}

AUB={1,2,3,4,6}

(AUB)UC={1,2,3,4,5,6,7,8}

hence proved

(ii) B intersection C={6}

A intersection (B intersection C)= null set

A intersection B={3,4}

(A intersection B)intersection C= null set

Answer 2

$\huge \blue \gamma \pink{Answer} \blue \gamma$

Hope it helps