Question

Answer the question in the above picture ​

Answer 1

Answer:   2, (-5)

Step-by-step explanation:

Given equation:

$x^{2}+3x-10=0\\\\=>x^{2}+5x-2x-10=0\\\\x(x+5)-2(x+5)=0\\\\(x-2)(x+5)=0\\\\=>x=2\;\;\;\;or\;\;\;\;x=(-5)\\\\\\=>\alpha=2\\\| \;\;\;\beta= \;-5$

$Learning\;\;together\;:)$

Answer 2

Answer:

X=2&-5

Step-by-step explanation:

${x}^{2} + 3x - 10 = 0$

${x}^{2} + 5x - 2x - 10 = 0$

$x(x + 5) - 2(x + 5) = 0$

$(x - 2)(x + 5) = 0$

$x = 2 \: \: and \: \: x = - 5$

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