Question

Answer the question in the attachment​

Answer 1

$\frac{ {a}^{2} }{bc} + \frac{ {b}^{2} }{ca} + \frac{ {c}^{2} }{ab} \\ = \frac{ {a}^{3} + {b}^{3} + {c}^{3} }{abc} \\ \\ = \frac{(a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc + ca) + 3abc }{abc} \\ \\ given = a + b + c = 0 \\ putting \: in \: the \: equation \\ = \frac{0 + 3abc}{abc} \\ \\ = 3$

Answer 2

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